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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: what is the electric field at the centre of the cubical conducting surface[charged]? n hwt is the po
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Mr.Nasty ® Retired from Action. (1460)

Olaaa!! Perrrfect answer. 260  [340 rates]

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\phi_ \mathrm{E} = - \int_C \mathbf{E} \cdot \mathrm{d} \mathbf{\ell}

where C is an arbitrary path connecting the point with zero potential to the point under consideration.

 

So Aditya's point does not stand. E will be zero, V() will not be determinable.....


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  this reply:   7 points  (with Olaaa!! Perrrfect answer.   in 2   votes   )     [?]
 
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