Messages posted by shubhayan_c

Q = CV

Applying on C2 we get voltage across it as 13.3 Mega volt (Given Q=40 & C = 3 micro Farad)

The potential across C1 and C2 will be same as they are in parallel

Charge on C1 using the above formula comes out to be 79.8 C (C= 6 micro Farad V= 13.3 Mega Volt)

really nice work

Net Electric Force = KQe/R^2 + Kqe/r^2 (Where Q = 2nC q= -5nC, R = .2m, r = .6m, e= Charge onElectro)

= KeX 10^-9(2/.2^2 - 5/.6^2) (K = 9 X 10^9)

= 9e(50 + 13.9)= 9e X 63.9 (Though the charge is -ve, dirn of field is along d other field so + sign)

= 5.751 X 10^-17 Newtons

Net Electric Field = Net Electric Force/ Charge (F =qE)= 63.1 X 9 =575.1 N/C

Force Between the particles is coming out to be 36kNewtons. Didn't understand the latter part

Don't beat the hell out of definition jus keep in mind that any surface which is completely closed is gaussian surface. Symmetry is just for convenience not a compulsion. A hemisphere can be considered as a gaussian surface if d base is closed(unlike a bowl(katori))

Mine n dhruvs guitar

Mine n dhruvs guitar

incredible!!!!!!! keep up d gud work

u cn find it in every buk wts so spl in it :P

u cn it in every buk wts so spl in it :P

When 220V flows thru d wire immense heat is produced V^2/R. which melts d wire.

@Aman - You should know dat resistance doesn't depend on voltage or current. As R = (rho * length)/area.

Hey Buddy,

Both are good all depends on your choice. Choose the stream in which you are more interested rather than thinking of the college. Any remember if you are good in your academics & skills you'll be placed in a good company irrespective of the college you are studying in. As when company recruits a student it's his performance that matter and not the reputation of the college.

1 Coloumb = 6.25 X 10^18 electrons (q = ne put q =1 and e =1.6 X 10^-19 to d value of n)

Electron transfer rate = 10^9 /s (Given)

Time required = (6.25 X 10^18)/10^9

Time = 6.25 X 10^9 seconds (considering no electron loss in path)

Give a diagram dude its really difficult to figure out d ckt from d explanation

good lines bt still thrs scope fr improvement

nice 1.really gud

nice 1

@GEET - 1st u vote then expect others 2 do so :). BTW my vote goes to mmmmmm.......mmmmmmmm......... All r gr8 at their respective place so its impossible for me 2 choose. (Not 2 considered a diplomatic answer)

Hey very nice move dat you've decided to do give a shot at JEE without any coaching. IIT-JEE is an exam focussed on ur application portion rather than your knowledge portion. So I think once you struggle with your subjects and overcome them your application portion becomes very strong unlike a coaching institute student who doesn't have his own time on books as they are wasted(not utilized fully) on school & coaching. Go on and remember the more you sweat in peace the less you bleed in war.

Hey Bhavya don't worry as these test which coaching institute conducts are above JEE level and they are to dent your confidence so that you start putting more effort than what u were giving before and also not to make you over-confident. These marks hardly matter, coz at the end off the day it depends on your JEE OMR sheet. Usually maths scores are lower than others in every engg entrance so dnt worry abt that its d same case with almost 90% aspirants for JEE.