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26 Jan 2010 20:50:00 IST
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There is an irregular-shaped sealed vessel containing some water. How can we determine whether the vessel is half-filled, more than half-filled or less than half-filled?*The vessel is the only one of its kind available and hence, an extra vessel can't be used for this purpose.
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26 Jan 2010 20:50:56 IST
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I was asked this question in my KVPY interview on 23rd January, 2010.............
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Common sense is not very common. --- Voltaire
Man is born free, but is everywhere in chains.-------Jean Jacques Rosseau
The rule of SATAN is inevitable~~~~~~transmigrator
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26 Jan 2010 20:51:32 IST
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The interviewer gave me a hint: YOU CAN USE A THREAD
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Common sense is not very common. --- Voltaire
Man is born free, but is everywhere in chains.-------Jean Jacques Rosseau
The rule of SATAN is inevitable~~~~~~transmigrator
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27 Jan 2010 23:26:25 IST
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No attempts?
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Common sense is not very common. --- Voltaire
Man is born free, but is everywhere in chains.-------Jean Jacques Rosseau
The rule of SATAN is inevitable~~~~~~transmigrator
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27 Jan 2010 23:28:27 IST
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Plz experts n non-experts.............
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Common sense is not very common. --- Voltaire
Man is born free, but is everywhere in chains.-------Jean Jacques Rosseau
The rule of SATAN is inevitable~~~~~~transmigrator
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27 Jan 2010 23:28:48 IST
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Atleast try
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Common sense is not very common. --- Voltaire
Man is born free, but is everywhere in chains.-------Jean Jacques Rosseau
The rule of SATAN is inevitable~~~~~~transmigrator
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29 Jan 2010 21:28:50 IST
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Isn't there even a single person in this so-called vibrant forum to atleast try......................N are the experts sleeping?
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Common sense is not very common. --- Voltaire
Man is born free, but is everywhere in chains.-------Jean Jacques Rosseau
The rule of SATAN is inevitable~~~~~~transmigrator
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29 Jan 2010 22:08:25 IST
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do we know the density or any other parameters. do reply
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30 Jan 2010 10:26:52 IST
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No we don't...................The only thing we know is that the vessel is sealed and there is some water inside.......
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Common sense is not very common. --- Voltaire
Man is born free, but is everywhere in chains.-------Jean Jacques Rosseau
The rule of SATAN is inevitable~~~~~~transmigrator
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30 Jan 2010 13:02:37 IST
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what was the reply you gave to the interviewer. because i have seen these type of questions and there we have to use calorimetry but then also we know the specific heat of the material or the thermal capacity of the system. since the interviewer has told us that the vessel is the only one available so can we be a liittle imaginative and remove a very small piece and determine its thermal capacity. do reply.
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30 Jan 2010 13:44:21 IST
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I simply replied: 'Sir, I donot know', after pondering over it for abt 20 secs.............They don't give u much time....... But if the vessel is massless, we can answer this question very easily. All we have to do is immerse the vessel completely in a bucket of water and weigh the water displaced..............Then, the vessel containing water is weighed and its mass is compared with the mass of displaced water. ***The mass of water displaced = Mass of water that fills the vessel completely May be, the interviewer meant a massless vessel..............I should have asked him..............
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Common sense is not very common. --- Voltaire
Man is born free, but is everywhere in chains.-------Jean Jacques Rosseau
The rule of SATAN is inevitable~~~~~~transmigrator
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30 Jan 2010 16:26:28 IST
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the vessel itself cannot be massless. otherwise we could just lift and feel the weight of the water. this would defeat the whole purpose of the question, also i can't understand what was the purpose of "USING A THREAD" . if we dont know the density what are we supposed to do by measuring its volume
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1 Feb 2010 13:20:15 IST
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if a thread is given then simply hang the vessel $useT+force due to fluid=Mgis it correct!!!???
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1 Feb 2010 19:45:42 IST
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sol is very simple take a look : take the thread and put it in the toe end of the vessel and keeping the tread on the sufrace measure the curved surface horizontal length . mark on the thread .this mark measures the actual height of irrregular vessel. like ways also find the height of water in the same way . if the water height is half of the total length then it is half filled
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2 Feb 2010 17:42:17 IST
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Take a beaker full of water. Immerse the irregular vessel into the beaker by applying force and lift it back. Certain height (h1) of water has overflowed. Now using a thread float the irregular vessel and note the rise in water level of beaker(h2). If h2>h1/2 Water inside the irregular vessel is more than half. If h2<h1/2 Water inside the irregular vessel is less than half. If h2=h1/2 Water inside the irregular vessel is half. HERE IT IS ASSUMED THAT VESSEL IS VERY THIN AND MASSLESS!!! OTHERWISE I HAVE NO ANSWER!?
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20 Feb 2010 00:58:14 IST
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ok.. maybe its a bit funny, but why can't we just tap th vessel hard on the sides at several locations and from the sound determine the height of the water... then we can find the ratio of the total volume and water-volume easily i suppose?
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20 Feb 2010 14:53:51 IST
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Ok! i think i nw hav a so calld serious answr (bt my earlier method shud also b fine ;-( ) ... here it is:a thread reminds me of a pendulum. now we use th time period equation for a pendulum. we tie the vessel to one end of the thread and suspend it from a point and lets say L is the length from the vessel to the pointof suspension. then, effective length of the simple pendulum system will be L+x ,where x is the length from the point where you tie the thread to the vessel to the centre of gravity of the vessel. Now measuring thew time period u get L+x and hence x. x will give us an idea of the water level in the vessel, and hence we can approximate an answer. also, this method has to assume that the perturbations in the water level in the vessel while it is swinging is negligible. Does this seem right?
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23 Feb 2010 13:44:45 IST
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23 Feb 2010 13:53:46 IST
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Common sense is not very common. --- Voltaire
Man is born free, but is everywhere in chains.-------Jean Jacques Rosseau
The rule of SATAN is inevitable~~~~~~transmigrator
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23 Feb 2010 14:02:42 IST
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In the above vessel , when the vessel in the orientation as shown, water will be in the bottom part which is DIVIDED into THREE "pool"s ... colored differently... the water level in them may not be the same coz they are not interconnected.... similarly, when you invert, water will flow into the red and blue chambers and they are not connected either (rotate the figure in 2 dimensions to get the actual thing)..so what do we do in thses situations???plus, suppose there are a ,t of different "pool"s in all directions of the vessel inner surface so that there is no "preferred" orientation... the situation seems to complicate if we also consider vessle wid holes (i think th name is "complex" polyhedron or smthing,,, m nt sure of this... will discuss ths later if it comes)... it maybe be difficult to "drain" the water completely to the lower surface if we have sort of a double-storey-building like structure of the vessel surface.
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