|
Author
|
Message
|
22 Nov 2010 20:51:23 IST
|
|
|
Time taken by a 836W heater to heat one litre of water from 10 degC to 40degC is
|
|
|
|
27 Nov 2010 11:54:34 IST
|
|
|
Q = m Cp (t2 - t1) Q = 1 X 4186 X (40 - 10) Q = 125580 Joules Power = Work Done / Time 836 = 125580/Time Time = 150.2 Seconds
|
this reply:
0 points
(with 0

in
0
votes
)
[?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|
|
|
Sponsored Links
|
|
|
|
|
|
|
|
|
|
|
|
|
preparing GATE 2010?
solved, model Papers,study Material
courses from Brilliant. Buy Now !
goiit.com/Brilliant-GATE
|
preparing GATE ?
online, Brilliant Tutorial courses
solved, model papers. Buy Now!
gateprep.com/GATE
|
preparing for IAS ?
Brilliant Tutorial's correspondence
Complete course. Buy Online Now !
goiit.com/Brilliant-UPSC-postal
|
preparing IES ?
solved, model paper, prelim monitor
online, study material. Buy Online!
go4ias.com/IES
|
preparing for BSNL JTO ?
solved, model paper, rank predictor
online, study material. Buy Online!
go4ias.com/BSNL-JTO
|
|
|