Three analog signals having bandwidths 1200 Hz, 600 Hz and 600 Hz, are sampled at their respective Nyquist rates, encoded with 12 bit words, and time division multiplexed. The bit rate for the multiplexed signal is

a) 115.2 kbps

b) 28.8 kbps

c) 57.6 kbps

d) 38.4kbps

According to Nyquist rate total samples=2(highest frquency)=2(1200)=2400 Samples per sec. Each SAmple require 12 bits.So total number of bits = 12*2400=28.8 KBPS

Answer b.28.8Kbps