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Ask experts Expert Question: There is an irregular-shaped sealed vessel containing some water. How can we determine whether the v
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"RAIDEN" :-) (470)

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well its easy..........take one tank and empty that irregular vessel and fill the water in the tank........now fill the irregular vessel to top........and then empty the vessel and fill that water in the other tank now compare both the tanks........ok
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Transmigrator (494)

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@raiden:- Its a sealed vessel......................Don't even think of tampering with the seal!


Common sense is not very common. --- Voltaire

Man is born free, but is everywhere in chains.-------Jean Jacques Rosseau

The rule of SATAN is inevitable~~~~~~transmigrator



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Transmigrator (494)

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@Yasin: Pressure at a depth at any pool = Pressureat the water surface in the pool + dgh

d= density of water


Common sense is not very common. --- Voltaire

Man is born free, but is everywhere in chains.-------Jean Jacques Rosseau

The rule of SATAN is inevitable~~~~~~transmigrator



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"RAIDEN" :-) (470)

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well then......let me think it more.....
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Yasin (51)

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Yasin (51)

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where will you put the mark?  here ofcourse the water is less than half, but the vessel could be more complicated!

 

oh well if u mark all the five different levels, i think u will divide it into SIX different parts, not two... isnt it? thee water levels are not connected and if we cut across all the marks, we weill have more than two parts ...

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Salonii Sharma (470)

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It's such a funny vessel. Lol.
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Yasin (51)

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physics can be funnier ;-)
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Transmigrator (494)

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Then lets put 5 different marks...............These 5 different marks collectively divide the vessel into two parts


Common sense is not very common. --- Voltaire

Man is born free, but is everywhere in chains.-------Jean Jacques Rosseau

The rule of SATAN is inevitable~~~~~~transmigrator



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Yasin (51)

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Then when you invert it, what if the water rises in some of these levels ans doest rise in some? to complicate matters, lets assume even a crazier shape!
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Yasin (51)

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n if u put five diff marks here, i think u;ll b dividint it into SIX diff parts, not two... wid th water levels different, if u cut thru ur marks, u'll land wid six parts wid water in five of them and none in one... isnt it??
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Yasin (51)

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Transmigrator (494)

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Do u think the interviewer had this model in mind.....................Well, i agree that my method won't apply here......


Common sense is not very common. --- Voltaire

Man is born free, but is everywhere in chains.-------Jean Jacques Rosseau

The rule of SATAN is inevitable~~~~~~transmigrator



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Mr.Nasty ® Retired from Action. (1460)

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U have a thread? Then u can make a pendulum. Time period can be known, effective length and g can be taken into account and center of mass can be found out. Proceed further and u can find your answer.


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Mr.Nasty ® Retired from Action. (1460)

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u do the math please.


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Yasin (51)

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mr nasty, as chandrashekhar pointed out, the vessel is irregular, so u can;t work out the centre of gravity easily.. plus, th vessel density also may nt b constant... plus, if th water is at multiple levels as shown, u can't work with even an approximate, or for that matter, accurate centre of mass of the vessel, coz u can;t find out th exact mass distribution of the various water pools..@chandrashekhar: well no! i also dnt think th examiner had this thing in mind, bt i;m still tryin to find a way assuming he had accounted for every odd possibility... did he definitely tell u that the vessel is a see--through?
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Yasin (51)

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I would like it if an expert could spend some time on this topic
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Mr.Nasty ® Retired from Action. (1460)

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@Yasin: You are assuming a lot about the vessel. Hang any shape, its center of mass would fall on the line of suspension. In any pendulum effective length is calculated between the point of suspension and the center of mass of the weight attached to it. since the length of the thread would be known, the center of mass would be easily calculable along the line of suspension. And apart from what the examiner has questioned, do NOT assume facts not mentioned. Otherwise you will be formulating the question. And also mark that in interviews like the one at KVPY they ask the question orally, and many times do not close loopholes. In fact they make up conditions as and if the candidate progresses with the right methodology. I tell this from first hand experience. I gave my KVPY interview in 2008.

 

Time period will vary with the level of water in the vessel.

 

Try drawing a graph between the water level and the time period for a simple pendulum with a hollow sphere for a bob, which is completely filled with water, and with a small hole at the bottom, such that water flows out during the oscillations.

 

Similar concept can be applied here.


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Yasin (51)

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@mrnasty: yeah i proposed th use of a pendulum, but shudnt we hav an approximate of th "position" of the centre of gravity of the vessel rather than only th "direction" (along the line of suspension as u said)... n ok u get one measurement here, but without knowing of th vessel, how do u estimate it? Try doing th same experiment wid a n iron-container filled with paper scrubs: u have to determine th height upto which th paper scrubs r filled... won't th extreme dfference between th densities of th vessel and th material inside cause a problem in th estimation??its fine if th examiner meant a simple vessel n i think he did so too, but just suppose he HAD closed all loopholes... th question is still worth a try... is there a method we could use universally, irrespective of how irregular th vessel is?
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Mr.Nasty ® Retired from Action. (1460)

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I get the magnitude and the direction both. From the surface at the point of suspension the distance to the center can be calculated using the effective length, no estimates, no approximations. Consider the point of suspension as the origin, u get a distance along the -y axis.
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